CUET Preparation Today
A family has two children, the probability that both the children are boys, if given that at least one of them is a boy is : |
$\frac{2}{3}$ $\frac{1}{4}$ $\frac{1}{3}$ $\frac{3}{4}$ |
$\frac{1}{3}$ |
The correct answer is Option (3) → $\frac{1}{3}$ $\text{P (Both Boys | At least one boy)=P(A|B)}$ $P(A|B)=\frac{P(A∩B)}{P(B)}=\frac{\frac{1}{4}}{\frac{3}{4}}=\frac{1}{3}$ |
