Two sources of light each with a power 200 W emit radiations of wavelength 10 nm and 600 nm, respectively. The ratio of number of photons emitted per second from two sources of photons, respectively will be:
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → 1 : 60
Power, $P=\frac{Energy(E)}{Time(t)}=\frac{n×h×v}{t}=\frac{nhc}{λt}$
where,
n = Number of photons emitted per second
v = frequency of radiation
t = time
$⇒n_1=\frac{P}{E_1}=\frac{200×t}{\frac{hc}{10×10^{-9}}}$
$⇒n_2=\frac{200×t}{\frac{hc}{600×10^{-9}}}$
$∴\frac{n_1}{n_2}=\frac{10×10^{-9}}{600×10^{-9}}=\frac{1}{60}$