Target Exam

CUET

Subject

Physics

Chapter

Communication

Question:

Two sources of light each with a power 200 W emit radiations of wavelength 10 nm and 600 nm, respectively. The ratio of number of photons emitted per second from two sources of photons, respectively will be:

Options:

1 : 60

6 : 1

1 : 1

60 : 1

Correct Answer:

1 : 60

Explanation:

The correct answer is Option (1) → 1 : 60

Power, $P=\frac{Energy(E)}{Time(t)}=\frac{n×h×v}{t}=\frac{nhc}{λt}$

where,

n = Number of photons emitted per second

v = frequency of radiation

t = time

$⇒n_1=\frac{P}{E_1}=\frac{200×t}{\frac{hc}{10×10^{-9}}}$

$⇒n_2=\frac{200×t}{\frac{hc}{600×10^{-9}}}$

$∴\frac{n_1}{n_2}=\frac{10×10^{-9}}{600×10^{-9}}=\frac{1}{60}$