If $y=x^2log_ex, $ then $\frac{d^2y}{dx^2}$ is equal to :
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → $3+2\log_e\, x$
$y=x^2\log_ex$
$\frac{dy}{dx}=2x\log_ex+x^2×\frac{1}{x}=2x\log_ex+x$
$⇒\frac{d^2y}{dx^2}=2\left(\log_ex+x^2×\frac{1}{x}\right)+1$
$=2(\log_ex+1)+1$
$=2\log_ex+3$