The value of $\int_0^{\frac{16π}{3}}|sin x|dx$ is:
Answer & explanation
Correct answer: option 3
$\int\limits_0^{\frac{16π}{3}}|sin x|dx=5\int\limits_0^{π}|sin x|dx+\int\limits_0^{π/3}|sin x|dx=5(2)+(1-\frac{1}{2})=\frac{21}{2}$
The value of $\int_0^{\frac{16π}{3}}|sin x|dx$ is:
Correct answer: option 3
$\int\limits_0^{\frac{16π}{3}}|sin x|dx=5\int\limits_0^{π}|sin x|dx+\int\limits_0^{π/3}|sin x|dx=5(2)+(1-\frac{1}{2})=\frac{21}{2}$