Number of critical points of $f(x) =\frac{|x^2-1|}{x^2}$ is

0 1 2 none of these

2

Clearly f(x) is not differentiable at x = 1 and x = -1 (x = 0 is not a critical point as it is not in the domain). Therefore 1 and -1 are critical points. Hence (C) is the correct answer.