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Number of critical points of $f(x) =\frac{|x^2-1|}{x^2}$ is |
0 1 2 none of these |
2 |
Clearly f(x) is not differentiable at x = 1 and x = -1 (x = 0 is not a critical point as it is not in the domain). Therefore 1 and -1 are critical points. Hence (C) is the correct answer. |
