The integral $∫\frac{x^4+2}{x^2+1}dx $ is equal to
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → $\frac{1}{3}x^3-x+3tan^{-1}x+c,$ where c is a constant
$∫\frac{x^4+2}{x^2+1}dx$
so $∫\frac{x^4+2}{x^2+1}dx=\int x^2-1+\frac{3}{x^2+1}dx$
$=\frac{x^3}{3}-x+3\tan^{-1}x+C$ using long division