When a deuteron is bombarded on ${ }_8^{16} O$ nucleus, an $\alpha$-particle is emitted. Other product nucleus is:
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → ${ }_7^{14} N$
The reaction can be written as -
${ }_8^{16} O+{ }_1^{2}H→{ }_2^{4}He+X$
According to conservation of Mass,
$16+2=4+m_x$
$m_x=14$
and, conservation of atomic number
$8+1=2+Z_x$
$Z_x=7$
$∴X={ }_7^{14} N$