In a single throw of a die, what is the probability of getting a number greater than 3.

$\frac{1}{2}$

Total possible numbers appear of face of dice = ( 1 , 2 , 3 , 4 ,5 , 6 ) = 6

Total possible numbers appear of face of dice greater than 4  = ( 4 ,5 , 6 ) = 3

Probability of getting a number greater than 3 = \(\frac{ No. \; of \;Possible \; outcomes\;}{Total\; no.\; of\; outcomes\;}\)

= \(\frac{3}{6}\)

= \(\frac{1}{2}\)

The correct answer is option (1) : $\frac{1}{2}$