Two similar coils of radius r are placed concentrically with their planes at right angles to each other. The currents flowing in them are I and 3I, respectively. The resultant magnetic induction at the centre is |
$\frac{\sqrt{5}μ_0I}{2R}$ $\frac{\sqrt{10}μ_0I}{2R}$ $\frac{\sqrt{3}μ_0I}{2R}$ $\frac{\sqrt{3}μ_0I}{4R}$ |
$\frac{\sqrt{10}μ_0I}{2R}$ |
The correct answer is Option (2) → $\frac{\sqrt{10}μ_0I}{2R}$ $B = \frac{\mu_0 I}{2r}$ $B_1 = \frac{\mu_0 I}{2r}$ $B_2 = \frac{\mu_0 (3I)}{2r} = \frac{3\mu_0 I}{2r}$ $\text{Fields are perpendicular}$ $B_{\text{net}} = \sqrt{B_1^2 + B_2^2}$ $B_{\text{net}} = \frac{\mu_0 I}{2r}\sqrt{1^2 + 3^2}$ $B_{\text{net}} = \frac{\mu_0 I}{2r}\sqrt{10}$ The resultant magnetic induction is $\frac{\mu_0 I \sqrt{10}}{2r}$. |