If sin θ + cos θ = \(\sqrt {3}\)cos θ, then value of cot θ is?
Answer & explanation
Correct answer: option 4
sin θ + cos θ = \(\sqrt {3 }\)cos θ
divide by cos θ
⇒ tan θ + 1 = \(\sqrt {3 }\)
⇒ tan θ = \(\sqrt {3 }\) - 1
⇒ cot θ = \(\frac{1}{\sqrt {3 } - 1}\)
= \(\frac{1}{\sqrt {3 } - 1}\) × \(\frac{\sqrt {3 } + 1}{\sqrt {3 } + 1}\)
= \(\frac{√3 + 1}{2}\)