A solenoid has a core of a material with a relative permeability of 500. The windings of the solenoid are insulated from the core and carry a current of 0.5 A. If the number of turns is 2000 per metre, the magnetic intensity is |
$4 × 10^3\, A m^{-1}$ $10^3\, A m^{-1}$ $0.2 π \, A m^{-1}$ $0.4 π \, A m^{-1}$ |
$10^3\, A m^{-1}$ |
The correct answer is Option (2) → $10^3\, A m^{-1}$ Given: Relative permeability: $\mu_r = 500$ Current: $I = 0.5$ A Number of turns per unit length: $n = 2000 \ \text{turns/m}$ Magnetic field intensity inside solenoid (independent of core material): $H = nI$ $H = 2000 \times 0.5 = 1000 \ \text{A/m}$ Answer: $H = 1000 \ \text{A/m}$ |