What is the value of van't Hoff factor for complete dissociation of $K_2SO_4$?
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → 3.00
K₂SO₄ dissociates completely in water as:
$\text{K}_2\text{SO}_4 \rightarrow 2\text{K}^+ + \text{SO}_4^{2-}$
- Total ions formed = $2(K^+)+1(SO_4^{2-})=3$
So, the van’t Hoff factor $i$ = 3.