Practicing Success
Practicing Success
CUET Preparation Today
Find the slope of the tangent to given curve at the indicated point as instructed: y =\( {x }^{4 } \) - 6\( { x}^{ 3} \) + 13\( { x}^{ 2} \) + 10x + 5 at (0,5) : |
y = 10x + 5 13x + y = 5 x + y = 5 x + 10y = 5 |
y = 10x + 5 |
Slope of tangent is $\frac{dy}{dx}=4x^3-18x^2+26x+10$ at (0, 5) $\frac{dy}{dx}=10$ Equation of tangent is $y - 5 = 10(x-0)$ $y=10x+5$ |
