A bag contains 17 tickets numbered 1 to 17. A ticket is drawn and replaced, then one more ticket is drawn and replaced. Probability that the first number drawn is even and the second is odd is

$\frac{72}{289}$

Let A be the event that first drawn number is even and B be event that the second drawn number is odd.

Total number of even numbers  = $[\frac{17}{2}] = 8$

$⇒  P(A)  =\frac{8}{47}$  and  $P(B)  =\frac{9}{17}$  $⇒   P(A ∩B) =\frac{72}{289}$