Practicing Success
Practicing Success
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If $ω$ is a complex cube root of unity, and $A =\begin{bmatrix}ω&0\\0&ω\end{bmatrix}$, then $A^{100}$ is equal to |
$A$ $-A$ $O$ none of these |
$A$ |
We have, $A =ω\begin{bmatrix}1&0\\0&1\end{bmatrix}=ω\,I_2$ $∴A^{100}=ω^{100}(I_2)^{100}=ω^{100}I_2=ω\,I_2=A$. |
