AB = 80 m, BC = 60 m

DF = 50 m, GE = 50 m

HE = 100m

Area of whole figure is:

7400 m²

In Δ ABC,

AC² = AB² + BC² = 80² + 60² = 6400 + 3600 = 10000

AC = 100 m

and Area of Δ ABC = \(\frac{1}{2}\) × AB × BC = \(\frac{1}{2}\) × 80 × 60 = 2400 m²

In Δ ACE,

AC = 100 m, EH = 100 m

Therefore,

Area of Δ ACE = \(\frac{1}{2}\) × AC × EH = \(\frac{1}{2}\) × 100 × 100 = 5000 m²

Hence,

Area of whole figure = Area of Δ ABC + Area of Δ ACE = 2400 + 5000 = 7400 m²