Which of the following statements are true?
(A) The function $f(x)=\frac{x^4}{4}-\frac{4}{3}x^3+\frac{x^2}{2}+6x$ has 3 critical points.
(B) The function $f(x) = |x|+ 3$ has no minimum value.
(C) A local maximum value is always the absolute maximum value.
(D) $f(x) = x^2$ has minima at $x=0$.
Choose the correct answer from the options given below:
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → (A) and (D) only
$\text{(A)}\;f(x)=\frac{x^4}{4}-\frac{4}{3}x^3+\frac{x^2}{2}+6x.$
$f'(x)=x^3-4x^2+x+6.$
$x^3-4x^2+x+6=(x-2)(x^2-2x-3)=(x-2)(x-3)(x+1).$
$\text{Critical points: }x=-1,2,3.$
$\Rightarrow \text{3 critical points.}$
$\text{(A) True.}$
$\text{(B)}\;f(x)=|x|+3.$
$\text{Minimum occurs at }x=0,\;f(0)=3.$
$\Rightarrow \text{Statement is false.}$
$\text{(C)}\;\text{Local maximum need not be absolute maximum.}$
$\Rightarrow \text{False.}$
$\text{(D)}\;f(x)=x^2.$
$f'(x)=2x=0 \Rightarrow x=0.$
$f''(x)=2>0 \Rightarrow \text{minimum at }x=0.$
$\Rightarrow \text{True.}$
$\text{Correct statements: (A) and (D).}$