The interval in which $f(x)=\cot^{-1} x+ x$ increases is
Answer & explanation
Correct answer: option 1
Given, $f(x)=\cot^{-1} x+ x$,
Differentiating both sides we get, $f'(x)=\frac{-1}{1+x^2}+1$
or $f'(x)=\frac{-1+1+x^2}{1+x^2}$ or $f'(x)=\frac{x^2}{1+x^2}$
Clearly, $f'(x)>0$ for all x.
So, $f(x)$ increasing in $(-∞,∞)$