A plane electromagnetic wave of frequency 40 MHz travels in free space in the X-direction. At some point and at some instant, the electric field E has its maximum value of 750 N/C in Y-direction, the propagation constant of the wave will be:
Answer & explanation
Correct answer: option 2
K = $\frac{2 \pi}{\lambda}=\frac{2 \times 3.14}{7.5}$ = 0.838 m–1