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A discrete random variable X has the following probability distribution:
The value of b is: |
$\frac{1}{25}$ $\frac{1}{5}$ $\frac{1}{22}$ 1 |
$\frac{1}{22}$ |
The correct answer is Option (3) - $\frac{1}{22}$ $\sum P(X=x) = 1$ $b + 3b + 5b + 3b + 4b + 6b = 1$ $22b = 1$ $b = \frac{1}{22}$ The value of $b$ is $\frac{1}{22}$. |
