The orthogonal trajectories of the family of curves $y=C x^2$, (C is an arbitrary constant), is
Answer & explanation
Correct answer: option 1
The equation of the given family of curves is
$y=C x^2$ .......(i)
Differentiating (i) w.r.t. $x$, we get
$\frac{d y}{d x}=2 C x$ .....(ii)
Eliminating $C$ between (i) and (ii), we obtain
$y=\left(\frac{1}{2 x} \frac{d y}{d x}\right) x^2 \Rightarrow 2 y=x \frac{d y}{d x}$ .......(iii)
This is the differential equation of the family of curves given in (i).
The differential equation of the orthogonal trajectories of (i) is obtained by replacing $\frac{d y}{d x}$ by $-\frac{d x}{d y}$ in equation (iii).
Replacing $\frac{d y}{d x}$ by $\frac{-d x}{d y}$ in (iii), we obtain
$2 y=-x \frac{d x}{d y} \Rightarrow 2 y d y=-x d x$
On integrating, we obtain
$y^2=-\frac{x^2}{2}+C \Rightarrow x^2+2 y^2=2 C$
This is the required family of orthogonal trajectories.