If cos x = $\frac{24}{25}, 0 ≤ x ≤ 90°,$ then the value of cot x + cosec x is :
Answer & explanation
Correct answer: option 3
cosx = \(\frac{24}{25}\)
{ cosx = \(\frac{B }{H}\) }
P² + B² = H²
P² + 24² = 25²
P = 7
Now,
cot x + cosec x
= \(\frac{B }{P}\) + \(\frac{H }{P}\)
= \(\frac{24 }{7}\) + \(\frac{25 }{7}\)
= \(\frac{49}{7}\)
= 7