Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Three-dimensional Geometry

Question:

If the direction cosines of a line are $\frac{1}{c},\frac{1}{c}, \frac{1}{c},$ then 

Options:

$0 < c < 1 $

$ c > 2 $

$ c < 2 $

$c = ± \sqrt{3}$

Correct Answer:

$c = ± \sqrt{3}$

Explanation:

If $\frac{1}{c},\frac{1}{c}, \frac{1}{c}$ are the direction cosines of a line, then $\frac{1}{c^2}+\frac{1}{c^2}+\frac{1}{c}=1 ⇒ c =± \sqrt{3} $