Alloy A contains metals x and y in the ratio 5 : 2 and alloy B contains these metals in the ratio 3 : 4. Alloy C is prepared by mixing A and B in the ratio 4 : 5. The percentage of y in alloy C is:

$44 \frac{4}{9} \%$

Alloy A 

      x   :   y 

      5   :   2

Alloy B,

      x   :   y 

      3   :   4

As A(x + y) = B(x + y), therefore,

Alloy C 

Ratio of x and y in Alloy C = 35 : 28 = 5 : 4,

Percentage of y in Alloy C = \(\frac{4}{9}\) x 100 = $44 \frac{4}{9} \%$