The in-radius of the triangle formed by the axes and the line 4x + 3y – 12 = 0 is:
Answer & explanation
Correct answer: option 3
$\frac{x}{3}+\frac{y}{4}=1$ ⇒ The sides are 3, 4, 5 $⇒\sqrt{a^2+b^2}=5$
$area\, Δ =\frac{1}{2}.3.4=6⇒r=\frac{Δ}{s}=\frac{6}{6}=1$