if f(x) = $\frac{1}{x} - 1$ , then f(f(1/x)) is

\[\frac{2-x}{x-1}\] \[\frac{x-1}{x}\] \[\frac{1-x}{x}\] 1-x

\[\frac{2-x}{x-1}\]

$f(\frac{1}{x}) = \frac{1}{1/x} - 1 = x-1$ $f(f(\frac{1}{x})) = \frac{1}{x-1} - 1 = \frac{2-x}{x-1}$