Target Exam

CUET

Subject

Section B1

Chapter

Three-dimensional Geometry

Question:

If the direction cosines of a line are $k$, $k$ and $k$, then

Options:

$k > 0$

$0 < k < 1$

$k = 1$

$k = \frac{1}{\sqrt{3}}$ or $-\frac{1}{\sqrt{3}}$

Correct Answer:

$k = \frac{1}{\sqrt{3}}$ or $-\frac{1}{\sqrt{3}}$

Explanation:

The correct answer is Option (4) → $k = \frac{1}{\sqrt{3}}$ or $-\frac{1}{\sqrt{3}}$ ##

Since, direction cosines of a line are $k, k$ and $k$.

$∴l = k, m = k \text{ and } n = k$

We know that, $l^2 + m^2 + n^2 = 1$

$\Rightarrow k^2 + k^2 + k^2 = 1 \Rightarrow 3k^2 = 1 \Rightarrow k^2 = \frac{1}{3}$

$∴k = \pm \frac{1}{\sqrt{3}}$