If the direction cosines of a line are $k$, $k$ and $k$, then |
$k > 0$ $0 < k < 1$ $k = 1$ $k = \frac{1}{\sqrt{3}}$ or $-\frac{1}{\sqrt{3}}$ |
$k = \frac{1}{\sqrt{3}}$ or $-\frac{1}{\sqrt{3}}$ |
The correct answer is Option (4) → $k = \frac{1}{\sqrt{3}}$ or $-\frac{1}{\sqrt{3}}$ ## Since, direction cosines of a line are $k, k$ and $k$. $∴l = k, m = k \text{ and } n = k$ We know that, $l^2 + m^2 + n^2 = 1$ $\Rightarrow k^2 + k^2 + k^2 = 1 \Rightarrow 3k^2 = 1 \Rightarrow k^2 = \frac{1}{3}$ $∴k = \pm \frac{1}{\sqrt{3}}$ |