If the points $(a, b), (c, d)$ and $(a + c, b+ d)$ are collinear, then |
$ab = cd$ $ac = bd$ $ab = bc$ $ad = bc$ |
$ad = bc$ |
The correct answer is Option (4) → $ad = bc$ Given points: $P(a,b),\ Q(c,d),\ R(a+c,b+d)$ are collinear. For collinearity, the slope of $PQ$ = slope of $QR$. Slope of $PQ = \frac{d-b}{c-a}$ Slope of $QR = \frac{(b+d)-d}{(a+c)-c} = \frac{b}{a}$ Hence, $\frac{d-b}{c-a} = \frac{b}{a}$ Cross-multiplying, $a(d - b) = b(c - a)$ $\Rightarrow ad - ab = bc - ab$ $\Rightarrow ad = bc$ Therefore, the required condition is $ad = bc$. |