Practicing Success

Target Exam

CUET

Subject

General Test

Chapter

Quantitative Reasoning

Topic

Algebra

Question:

The value of $\frac{\frac{1}{5}÷\frac{1}{5}×\frac{1}{5}}{\frac{1}{5}÷\frac{1}{5}of\frac{1}{5}}-4\frac{1}{5}÷105$ is :

Options:

0

2

10

5

Correct Answer:

0

Explanation:

The value of $\frac{\frac{1}{5}÷\frac{1}{5}×\frac{1}{5}}{\frac{1}{5}÷\frac{1}{5}of\frac{1}{5}}-4\frac{1}{5}÷105$

=$\frac{1}{5} ÷5-\frac{21}{5}$ ÷105

=$\frac{1}{5} ÷5 -\frac{1}{25}$

= $\frac{1}{25}$ - $\frac{1}{25}$  = 0