Practicing Success
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If x - \(\frac{1}{x}\) = 2\(\sqrt{3}\) then find the value of ( x + \(\frac{1}{x}\) )2 |
9 16 25 36 |
16 |
⇒ If x - \(\frac{1}{x}\) = a then x + \(\frac{1}{x}\) = \(\sqrt {a^2 + 4}\) Here, x - \(\frac{1}{x}\) = 2\(\sqrt{3}\), then ⇒ x + \(\frac{1}{x}\) = \(\sqrt {(2\sqrt{3})^2 + 4}\) = 4 ⇒ ( x + \(\frac{1}{x}\) )2 = 42 = 16 |
