Practicing Success
A Carnot engine, having an efficiency of h = 1/10 as heat engine, is used as a refrigerator. If the work done on the system is 10 J, the amount of energy absorbed from the reservoir at lower temperature is :- |
95 J 90 J 1 J 100 J |
95 J |
\(\text{Efficiency : }\eta = \frac{1}{\beta + 1}\) Also, \(\eta = \frac{1}{20}\) ⇒ \(\beta = 19 \) \(\beta = \frac{Q}{W}\) W = 5 ⇒ \(Q = 95 \text{ J} \) |