A Carnot engine, having an efficiency of h = 1/10 as heat engine, is used as a refrigerator. If the work done on the system is 10 J, the amount of energy absorbed from the reservoir at lower temperature is :-
Answer & explanation
Correct answer: option 1
\(\text{Efficiency : }\eta = \frac{1}{\beta + 1}\)
Also, \(\eta = \frac{1}{20}\)
⇒ \(\beta = 19 \)
\(\beta = \frac{Q}{W}\)
W = 5
⇒ \(Q = 95 \text{ J} \)