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If $a=12, b=-8$ and $c=-4$, then find the value of $a^3+b^3+c^3$ |
384 1152 -1448 2304 |
1152 |
We know that, if a + b + c = 0 then, $a^3+b^3+c^3$ = 3abc We have, $a=12, b=-8$ and $c=-4$ so a + b + c = 0 $a^3+b^3+c^3$ = 3 × 12 × -8 × -4 = 1152 |
