If x4 + frac1x^4 = 9602 find the value of x - 1/x

x⁴+\(\frac{1}{{x}^{4}}\) = 9602

x²+\(\frac{1}{{x}^{2}}\) =\(\sqrt {9602+2}\)=98

[If x⁴+\(\frac{1}{{x}^{4}}\) = m than x²+\(\frac{1}{{x}^{2}}\) = \(\sqrt {m+2}=z\) and x-\(\frac{1}{x}\) =\(\sqrt {z-2}\)

x-\(\frac{1}{x}\) = \(\sqrt {98-2}\)=\(\sqrt {96}\)

x-\(\frac{1}{x}\) =4\(\sqrt {6}\)