If  x4 +\(\frac{1}{{x}^{4}}\) = 9602 find the value of x - \(\frac{1}{x}\)

2\(\sqrt {6}\) 4\(\sqrt {6}\) 6\(\sqrt {6}\) 7\(\sqrt {6}\)

4\(\sqrt {6}\)

x4+\(\frac{1}{{x}^{4}}\) = 9602 x2+\(\frac{1}{{x}^{2}}\) =\(\sqrt {9602+2}\)=98 [If x4+\(\frac{1}{{x}^{4}}\) = m than x2+\(\frac{1}{{x}^{2}}\) = \(\sqrt {m+2}=z\) and x-\(\frac{1}{x}\) =\(\sqrt {z-2}\) x-\(\frac{1}{x}\) = \(\sqrt {98-2}\)=\(\sqrt {96}\) x-\(\frac{1}{x}\) =4\(\sqrt {6}\)