1000 turns per meter are wound over a Rowland ring of ferromagnetic material. On passing a current of 2 ampere in the coil, a magnetic field of 10 Wb/m2 is produced in it.
The magnetising force generated in the material will be :
Answer & explanation
Correct answer: option 4
$ H = \frac{NI}{2\pi r} = nI = 2\times 10^3A/m$