Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Wave Optics

Question:

Two slits are kept 1 mm apart and the screen is placed 1.0 m away. What is the fringe separation when blue-green light of wavelength 500 nm is used?

Options:

0.05 mm

0.5 mm

5.0 mm

50.0 mm

Correct Answer:

0.5 mm

Explanation:

Fringe Width is $\beta = \frac{\lambda D}{d} = \frac{500\times 10^{-9}\times 1}{10^{-3}} = 500\times 10^{-6} =0.5 mm$