Practicing Success
Bottles containing C6H5I and C6H5CH2I lost their original labels. They were labelled A and B for testing. A and B were separately taken in test tubes and boiled with NaOH solution. The end solution in each tube was made acidic with dilute HNO3 and some AgNO3 solution added. Solution B gave a yellow precipitate. Which one of the following statements is true for the experiment? |
Addition of HNO3 was unnecessary A was C6H5I A was C6H5CH2I B was C6H5I |
A was C6H5I |
The correct answer is option 2. A was C6H5I Since the bottle labelled A does not give a precipitate. Therefore, A was \(C_6H_5I\). Substance labelled B gives a yellow precipitate. Thus, B was \(C_6H_5CH_2I\). |