CUET Preparation Today
If the normal to the curve $y=f(x)$ at the point (3, 4) makes an angle $\frac{3\pi }{4}$ with the positive x-axis then $f'(3)=$ _________. |
-1 1 $-\frac{3}{4}$ $\frac{3}{4}$ |
1 |
The correct answer is Option (2) → 1 $y=f(x)$ Point (3, 4) slope of normal = $\tan\frac{3π}{4}=-1$ slope of normal = $\frac{-1}{f'(x)}$ so basically $\frac{-1}{f'(3)}=-1$ $⇒f'(3)=1$ |
