Let ΔABC ∼ΔPQR and $\frac{ar(ΔABC)}{ar(ΔQPR)}=\frac{64}{169}$. If Ab = 10 cm, BC = 7 cm and AC = 16 cm, then Pr (in cm) is equal to :

26

We have a concept=

according to the given data,

\(\frac{ ar(ΔABC)}{ ar(ΔQPR) }\) = \(\frac{AC^2}{PR^2}\)

= \(\frac{64}{169}\) = \(\frac{16^2}{PR^2}\)

= \(\frac{8}{13}\) = \(\frac{16}{PR}\)

= PR = (13 × 16) × \(\frac{1}{8}\)= 26 cm