If $\begin{bmatrix} 1 & 0 \\-1 & 7 \end{bmatrix}=A$ and $A^2-8A+KI=O,$ then the value of K is :
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → 7
$A=\begin{bmatrix} 1 & 0 \\-1 & 7 \end{bmatrix}$
$A^2=\begin{bmatrix} 1 & 0 \\-1 & 7 \end{bmatrix}\begin{bmatrix} 1 & 0 \\-1 & 7 \end{bmatrix}=\begin{bmatrix} 1 & 0 \\-8 & 49 \end{bmatrix}$
$A^2-8A=\begin{bmatrix} 1 & 0 \\-8 & 49 \end{bmatrix}-\begin{bmatrix} 8 & 0 \\-8 & 56\end{bmatrix}=\begin{bmatrix} -7 & 0 \\0 & -7 \end{bmatrix}$
so $KI=-(A^2-8A)=7\begin{bmatrix} 1 & 0 \\0 & 1 \end{bmatrix}$
so $K=7$