Calculate the molarity of a solution containing 5 g of NaOH in 450 mL solution.

0.178 M 0.278 M 0.378 m 0.478 M

0.278 M

No of moles of NaOH = \(\frac{5}{40}\) = 0.125 mol Molarity = \(\frac{\text{no of moles of solute}}{\text{Volume of solution (in ml)}}\) x 1000 M = \(\frac{0.125}{450}\) x 1000 = 0.278 M