If x, y are acute angles, where 0 < x + y < 90° and sin (3x - 40°) = cos(3y + 40°), then the value of tan(x + y) is equal to:
Answer & explanation
Correct answer: option 2
sin (3x - 40°) = cos(3y + 40°)
Formula used :-
sin A = cos B
Then , A + B = 90º
So, ( 3x - 40º + 3y + 40º ) = 90º
x + y = 30º
Now, tan( x + y )
= tan30º
= \(\frac{1 }{ √3 }\)