Practicing Success
Practicing Success
CUET Preparation Today
| The value of \(\int_{0}^{1} { e }^{ -2x } dx\) |
\[\frac{{ e }^{ -2} -1}{-2}\]
\[\frac{{ e }^{- 2 } -1}{2}\] \[\frac{-{ e }^{ -2 } +1}{-2}\] \[\frac{-{ e }^{ 2 } +1}{2}\] |
| \[\frac{{ e }^{ -2} -1}{-2}\] |
| the integral will be \[\frac{{ e }^{ -2x } }{-2}\] |
