For the given diagram of barrier potential of this diode is 0.5 V. The value of current in the circuit is:
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → $\frac{1}{20} A$
Net potential across the Resistor,
$Emf_{net}=Emf-V_{barrier}$
$=(5-0.5)V$
$=4.5V$
and,
$V=IR$ [Ohm's law]
$I=\frac{V_{net}}{R}=\frac{4.5}{90}=\frac{45}{900}=\frac{1}{20}A$