For what value of $k$, the following system of equations has infinitely many solutions?
$x+2y= 5,3x+ky = 15$
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → 6
Given system:
$x+2y=5$
$3x+ky=15$
For infinitely many solutions, the equations must be dependent:
$\frac{a_1}{a_2}=\frac{b_1}{b_2}=\frac{c_1}{c_2}$
Write in standard form:
$x+2y-5=0$
$3x+ky-15=0$
So
$\frac{1}{3}=\frac{2}{k}=\frac{-5}{-15}$
$\frac{1}{3}=\frac{2}{k}=\frac{1}{3}$
From $\frac{2}{k}=\frac{1}{3}$
$k=6$