CUET Preparation Today
Find an anti-derivative of the function $3x^2 + 4x^3$ using the method of inspection. |
$x^2 + x^3$ $6x + 12x^2$ $\frac{3x^3}{2} + \frac{4x^4}{3}$ $x^3 + x^4$ |
$x^3 + x^4$ |
The correct answer is Option (4) → $x^3 + x^4$ We look for a function whose derivative is $3x^2 + 4x^3$. $\frac{d}{dx} (x^3 + x^4) = 3x^2 + 4x^3.$ Therefore, an anti derivative of $3x^2 + 4x^3$ is $x^3 + x^4$. |
