Suppose we have a right angled triangle ABC with height AB=3 unit and base BC=4 unit. Let the angle ACB be x and the angle BAC equals to y. Then answer the following:

x is equal to

$\tan^{-1}(1/2)$ $\tan^{-1}(1/3)$ $\tan^{-1}(3/4)$ $\tan^{-1}(4/3)$

$\tan^{-1}(3/4)$

$\tan x=AB/BC=3/4$. Hence $x=\tan^{-1}(3/4)$