If 8K6 + 15K3 - 2 = 0
Find K + \(\frac{1}{K}\) (positive value)
Answer & explanation
Correct answer: option 1
Formula → 15K3 = 16K3 - K3
8K6 + 16K3 - K3 - 2 = 0
8K3 (K3 + 2) - 1 (K3 + 2)= 0
K3 = \(\frac{1}{8}\) or K3 = -2
So if, K3 = \(\frac{1}{8}\) → K = \(\sqrt [3]{\frac{1}{8}}\) = \(\frac{1}{2}\)
⇒ K + \(\frac{1}{K}\) = \(\frac{1}{2}\) + 2 = \(\frac{5}{2}\) or 2\(\frac{1}{2}\)