The value of current through an inductor of inductance 2.0 H and negligible resistance when connected to an AC source of 157 V, 50 Hz will be:
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → $\frac{1}{4}$ A
Using Ohm's law,
Current, $I=\frac{V}{Z_L}=\frac{V}{2\pi vL}$
$=\frac{157}{2\pi×50×2.0}$
$=\frac{157}{628.3}=0.25A$