Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Alternating Current

Question:

Options:

a

b

c

d

Correct Answer:

a

Explanation:

$V_{rms} = \frac{\int_0^\frac{T}{4}{V^2dt}}{\frac{T}{4}}$

$ V = \frac{4V_0}{T} t$

$V_{rms} = \frac{\int_0^\frac{T}{4}{(\frac{4V_0}{T} t)^2dt}}{\frac{T}{4}} = \frac{V_0}{\sqrt 3}$