The overall order of a reaction which has the rate expression.
Rate \(= k [A]^{2/4}[B]^2\) will be
Answer & explanation
Correct answer: option 2
The correct answer is option 2. \(\frac{5}{2}\).
To determine the overall order of a reaction given its rate expression, we need to sum the exponents of the concentration terms in the rate law.
Given the rate expression:
\(\text{Rate} = k [A]^{2/4}[B]^2 \)
Steps to Determine the Overall Order:
For \( [A] \), the exponent is \( \frac{2}{4} \).
For \( [B] \), the exponent is \( 2 \).
Calculate the overall order by adding the exponents of all concentration terms.
\(\text{Overall order} = \left(\frac{2}{4}\right) + 2\)
Simplify \( \frac{2}{4} \) to \( \frac{1}{2} \).
\(\text{Overall order} = \frac{1}{2} + 2 = \frac{1}{2} + \frac{4}{2} = \frac{5}{2}\)
Conclusion
The overall order of the reaction is \( \frac{5}{2} \). Therefore, the correct answer is: 2. \(\frac{5}{2}\)